A stallholder had the same number of pears, peaches and guavas at first. After 89 guavas, some pears and peaches were set aside, there were 174 fruits left. There were five times as many pears as peaches left. The number of guavas left was 13 fewer than the number of pears. How many peaches were set aside?
| |
Pears |
Peaches |
Guavas |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 89 |
|
| After |
5 u |
1 u |
5 u - 13 |
174 |
Total number of fruits in the end
= 5 u + 1 u + 5 u - 13
= 11 u - 13
11 u - 13 = 174
11 u = 174 + 13
11 u = 187
1 u = 187 ÷ 11 = 17
Number of guavas at first
= 5 u - 13 + 89
= 5 x 17 - 13 + 89
= 85 - 13 + 89
= 161
The number of peaches and guavas at first was the same.
Number of peaches set aside
= 161 - 1 u
= 161 - 17
= 144
Answer(s): 144
