A stallholder had the same number of lemons, pomegranates and mangoes at first. After 57 mangoes, some lemons and pomegranates were removed, there were 105 fruits left. There were five times as many lemons as pomegranates left. The number of mangoes left was 27 fewer than the number of lemons. How many pomegranates were removed?
| |
Lemons |
Pomegranates |
Mangoes |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 57 |
|
| After |
5 u |
1 u |
5 u - 27 |
105 |
Total number of fruits in the end
= 5 u + 1 u + 5 u - 27
= 11 u - 27
11 u - 27 = 105
11 u = 105 + 27
11 u = 132
1 u = 132 ÷ 11 = 12
Number of mangoes at first
= 5 u - 27 + 57
= 5 x 12 - 27 + 57
= 60 - 27 + 57
= 90
The number of pomegranates and mangoes at first was the same.
Number of pomegranates removed
= 90 - 1 u
= 90 - 12
= 78
Answer(s): 78
