A stallholder had the same number of peaches, kiwis and chikoos at first. After 122 chikoos, some peaches and kiwis were given away, there were 119 fruits left. There were four times as many peaches as kiwis left. The number of chikoos left was 34 less than the number of peaches. How many kiwis were given away?
| |
Peaches |
Kiwis |
Chikoos |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 122 |
|
| After |
4 u |
1 u |
4 u - 34 |
119 |
Total number of fruits in the end
= 4 u + 1 u + 4 u - 34
= 9 u - 34
9 u - 34 = 119
9 u = 119 + 34
9 u = 153
1 u = 153 ÷ 9 = 17
Number of chikoos at first
= 4 u - 34 + 122
= 4 x 17 - 34 + 122
= 68 - 34 + 122
= 156
The number of kiwis and chikoos at first was the same.
Number of kiwis given away
= 156 - 1 u
= 156 - 17
= 139
Answer(s): 139
