A fruit seller had the same number of peaches, lemons and pomegranates at first. After 77 pomegranates, some peaches and lemons were removed, there were 111 fruits left. There were twice as many peaches as lemons left. The number of pomegranates left was 39 less than the number of peaches. How many lemons were removed?
| |
Peaches |
Lemons |
Pomegranates |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 77 |
|
| After |
2 u |
1 u |
2 u - 39 |
111 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 39
= 5 u - 39
5 u - 39 = 111
5 u = 111 + 39
5 u = 150
1 u = 150 ÷ 5 = 30
Number of pomegranates at first
= 2 u - 39 + 77
= 2 x 30 - 39 + 77
= 60 - 39 + 77
= 98
The number of lemons and pomegranates at first was the same.
Number of lemons removed
= 98 - 1 u
= 98 - 30
= 68
Answer(s): 68
