A fruit seller had the same number of mangosteens, peaches and kiwis at first. After 87 kiwis, some mangosteens and peaches were set aside, there were 177 fruits left. There were four times as many mangosteens as peaches left. The number of kiwis left was 12 less than the number of mangosteens. How many peaches were set aside?
| |
Mangosteens |
Peaches |
Kiwis |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 87 |
|
| After |
4 u |
1 u |
4 u - 12 |
177 |
Total number of fruits in the end
= 4 u + 1 u + 4 u - 12
= 9 u - 12
9 u - 12 = 177
9 u = 177 + 12
9 u = 189
1 u = 189 ÷ 9 = 21
Number of kiwis at first
= 4 u - 12 + 87
= 4 x 21 - 12 + 87
= 84 - 12 + 87
= 159
The number of peaches and kiwis at first was the same.
Number of peaches set aside
= 159 - 1 u
= 159 - 21
= 138
Answer(s): 138
