A stallholder had the same number of grapefruits, kiwis and pears at first. After 62 pears, some grapefruits and kiwis were removed, there were 157 fruits left. There were five times as many grapefruits as kiwis left. The number of pears left was 30 less than the number of grapefruits. How many kiwis were removed?
| |
Grapefruits |
Kiwis |
Pears |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 62 |
|
| After |
5 u |
1 u |
5 u - 30 |
157 |
Total number of fruits in the end
= 5 u + 1 u + 5 u - 30
= 11 u - 30
11 u - 30 = 157
11 u = 157 + 30
11 u = 187
1 u = 187 ÷ 11 = 17
Number of pears at first
= 5 u - 30 + 62
= 5 x 17 - 30 + 62
= 85 - 30 + 62
= 117
The number of kiwis and pears at first was the same.
Number of kiwis removed
= 117 - 1 u
= 117 - 17
= 100
Answer(s): 100
