A fruit seller had the same number of mangoes, pomegranates and lemons at first. After 105 lemons, some mangoes and pomegranates were taken out, there were 115 fruits left. There were thrice as many mangoes as pomegranates left. The number of lemons left was 11 less than the number of mangoes. How many pomegranates were taken out?
|
Mangoes |
Pomegranates |
Lemons |
Total |
Before |
1 |
1 |
1 |
|
Change |
- ? |
- ? |
- 105 |
|
After |
3 u |
1 u |
3 u - 11 |
115 |
Total number of fruits in the end
= 3 u + 1 u + 3 u - 11
= 7 u - 11
7 u - 11 = 115
7 u = 115 + 11
7 u = 126
1 u = 126 ÷ 7 = 18
Number of lemons at first
= 3 u - 11 + 105
= 3 x 18 - 11 + 105
= 54 - 11 + 105
= 148
The number of pomegranates and lemons at first was the same.
Number of pomegranates taken out
= 148 - 1 u
= 148 - 18
= 130
Answer(s): 130