A fruit seller had the same number of dragonfruits, persimmons and pomegranates at first. After 53 pomegranates, some dragonfruits and persimmons were given away, there were 199 fruits left. There were twice as many dragonfruits as persimmons left. The number of pomegranates left was 16 less than the number of dragonfruits. How many persimmons were given away?
| |
Dragonfruits |
Persimmons |
Pomegranates |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 53 |
|
| After |
2 u |
1 u |
2 u - 16 |
199 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 16
= 5 u - 16
5 u - 16 = 199
5 u = 199 + 16
5 u = 215
1 u = 215 ÷ 5 = 43
Number of pomegranates at first
= 2 u - 16 + 53
= 2 x 43 - 16 + 53
= 86 - 16 + 53
= 123
The number of persimmons and pomegranates at first was the same.
Number of persimmons given away
= 123 - 1 u
= 123 - 43
= 80
Answer(s): 80
