A fruit seller had the same number of pears, peaches and persimmons at first. After 138 persimmons, some pears and peaches were used, there were 114 fruits left. There were thrice as many pears as peaches left. The number of persimmons left was 19 less than the number of pears. How many peaches were used?
| |
Pears |
Peaches |
Persimmons |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 138 |
|
| After |
3 u |
1 u |
3 u - 19 |
114 |
Total number of fruits in the end
= 3 u + 1 u + 3 u - 19
= 7 u - 19
7 u - 19 = 114
7 u = 114 + 19
7 u = 133
1 u = 133 ÷ 7 = 19
Number of persimmons at first
= 3 u - 19 + 138
= 3 x 19 - 19 + 138
= 57 - 19 + 138
= 176
The number of peaches and persimmons at first was the same.
Number of peaches used
= 176 - 1 u
= 176 - 19
= 157
Answer(s): 157
