A grocer had the same number of peaches, pomegranates and mangosteens at first. After 118 mangosteens, some peaches and pomegranates were set aside, there were 90 fruits left. There were twice as many peaches as pomegranates left. The number of mangosteens left was 15 fewer than the number of peaches. How many pomegranates were set aside?
| |
Peaches |
Pomegranates |
Mangosteens |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 118 |
|
| After |
2 u |
1 u |
2 u - 15 |
90 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 15
= 5 u - 15
5 u - 15 = 90
5 u = 90 + 15
5 u = 105
1 u = 105 ÷ 5 = 21
Number of mangosteens at first
= 2 u - 15 + 118
= 2 x 21 - 15 + 118
= 42 - 15 + 118
= 145
The number of pomegranates and mangosteens at first was the same.
Number of pomegranates set aside
= 145 - 1 u
= 145 - 21
= 124
Answer(s): 124
