A fruit seller had the same number of guavas, kiwis and pears at first. After 95 pears, some guavas and kiwis were thrown away, there were 176 fruits left. There were twice as many guavas as kiwis left. The number of pears left was 19 fewer than the number of guavas. How many kiwis were thrown away?
| |
Guavas |
Kiwis |
Pears |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 95 |
|
| After |
2 u |
1 u |
2 u - 19 |
176 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 19
= 5 u - 19
5 u - 19 = 176
5 u = 176 + 19
5 u = 195
1 u = 195 ÷ 5 = 39
Number of pears at first
= 2 u - 19 + 95
= 2 x 39 - 19 + 95
= 78 - 19 + 95
= 154
The number of kiwis and pears at first was the same.
Number of kiwis thrown away
= 154 - 1 u
= 154 - 39
= 115
Answer(s): 115
