A fruit seller had the same number of guavas, mangoes and kiwis at first. After 38 kiwis, some guavas and mangoes were removed, there were 120 fruits left. There were twice as many guavas as mangoes left. The number of kiwis left was 30 less than the number of guavas. How many mangoes were removed?
| |
Guavas |
Mangoes |
Kiwis |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 38 |
|
| After |
2 u |
1 u |
2 u - 30 |
120 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 30
= 5 u - 30
5 u - 30 = 120
5 u = 120 + 30
5 u = 150
1 u = 150 ÷ 5 = 30
Number of kiwis at first
= 2 u - 30 + 38
= 2 x 30 - 30 + 38
= 60 - 30 + 38
= 68
The number of mangoes and kiwis at first was the same.
Number of mangoes removed
= 68 - 1 u
= 68 - 30
= 38
Answer(s): 38
