A store owner had the same number of peaches, dragonfruits and lemons at first. After 69 lemons, some peaches and dragonfruits were set aside, there were 191 fruits left. There were thrice as many peaches as dragonfruits left. The number of lemons left was 12 fewer than the number of peaches. How many dragonfruits were set aside?
| |
Peaches |
Dragonfruits |
Lemons |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 69 |
|
| After |
3 u |
1 u |
3 u - 12 |
191 |
Total number of fruits in the end
= 3 u + 1 u + 3 u - 12
= 7 u - 12
7 u - 12 = 191
7 u = 191 + 12
7 u = 203
1 u = 203 ÷ 7 = 29
Number of lemons at first
= 3 u - 12 + 69
= 3 x 29 - 12 + 69
= 87 - 12 + 69
= 144
The number of dragonfruits and lemons at first was the same.
Number of dragonfruits set aside
= 144 - 1 u
= 144 - 29
= 115
Answer(s): 115
