A fruit seller had the same number of pears, starfruits and pomegranates at first. After 100 pomegranates, some pears and starfruits were removed, there were 120 fruits left. There were thrice as many pears as starfruits left. The number of pomegranates left was 20 fewer than the number of pears. How many starfruits were removed?
| |
Pears |
Starfruits |
Pomegranates |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 100 |
|
| After |
3 u |
1 u |
3 u - 20 |
120 |
Total number of fruits in the end
= 3 u + 1 u + 3 u - 20
= 7 u - 20
7 u - 20 = 120
7 u = 120 + 20
7 u = 140
1 u = 140 ÷ 7 = 20
Number of pomegranates at first
= 3 u - 20 + 100
= 3 x 20 - 20 + 100
= 60 - 20 + 100
= 140
The number of starfruits and pomegranates at first was the same.
Number of starfruits removed
= 140 - 1 u
= 140 - 20
= 120
Answer(s): 120
