A stallholder had the same number of grapefruits, pears and guavas at first. After 39 guavas, some grapefruits and pears were set aside, there were 107 fruits left. There were thrice as many grapefruits as pears left. The number of guavas left was 19 fewer than the number of grapefruits. How many pears were set aside?
| |
Grapefruits |
Pears |
Guavas |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 39 |
|
| After |
3 u |
1 u |
3 u - 19 |
107 |
Total number of fruits in the end
= 3 u + 1 u + 3 u - 19
= 7 u - 19
7 u - 19 = 107
7 u = 107 + 19
7 u = 126
1 u = 126 ÷ 7 = 18
Number of guavas at first
= 3 u - 19 + 39
= 3 x 18 - 19 + 39
= 54 - 19 + 39
= 74
The number of pears and guavas at first was the same.
Number of pears set aside
= 74 - 1 u
= 74 - 18
= 56
Answer(s): 56
