A fruit seller had the same number of peaches, grapefruits and chikoos at first. After 82 chikoos, some peaches and grapefruits were sold, there were 189 fruits left. There were twice as many peaches as grapefruits left. The number of chikoos left was 11 less than the number of peaches. How many grapefruits were sold?
| |
Peaches |
Grapefruits |
Chikoos |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 82 |
|
| After |
2 u |
1 u |
2 u - 11 |
189 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 11
= 5 u - 11
5 u - 11 = 189
5 u = 189 + 11
5 u = 200
1 u = 200 ÷ 5 = 40
Number of chikoos at first
= 2 u - 11 + 82
= 2 x 40 - 11 + 82
= 80 - 11 + 82
= 151
The number of grapefruits and chikoos at first was the same.
Number of grapefruits sold
= 151 - 1 u
= 151 - 40
= 111
Answer(s): 111
