A store owner had the same number of peaches, grapefruits and persimmons at first. After 52 persimmons, some peaches and grapefruits were thrown away, there were 97 fruits left. There were four times as many peaches as grapefruits left. The number of persimmons left was 29 less than the number of peaches. How many grapefruits were thrown away?
| |
Peaches |
Grapefruits |
Persimmons |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 52 |
|
| After |
4 u |
1 u |
4 u - 29 |
97 |
Total number of fruits in the end
= 4 u + 1 u + 4 u - 29
= 9 u - 29
9 u - 29 = 97
9 u = 97 + 29
9 u = 126
1 u = 126 ÷ 9 = 14
Number of persimmons at first
= 4 u - 29 + 52
= 4 x 14 - 29 + 52
= 56 - 29 + 52
= 79
The number of grapefruits and persimmons at first was the same.
Number of grapefruits thrown away
= 79 - 1 u
= 79 - 14
= 65
Answer(s): 65
