A store owner had the same number of kiwis, grapefruits and pears at first. After 50 pears, some kiwis and grapefruits were removed, there were 114 fruits left. There were twice as many kiwis as grapefruits left. The number of pears left was 36 fewer than the number of kiwis. How many grapefruits were removed?
| |
Kiwis |
Grapefruits |
Pears |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 50 |
|
| After |
2 u |
1 u |
2 u - 36 |
114 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 36
= 5 u - 36
5 u - 36 = 114
5 u = 114 + 36
5 u = 150
1 u = 150 ÷ 5 = 30
Number of pears at first
= 2 u - 36 + 50
= 2 x 30 - 36 + 50
= 60 - 36 + 50
= 74
The number of grapefruits and pears at first was the same.
Number of grapefruits removed
= 74 - 1 u
= 74 - 30
= 44
Answer(s): 44
