A stallholder had the same number of mangosteens, lemons and peaches at first. After 90 peaches, some mangosteens and lemons were given away, there were 198 fruits left. There were four times as many mangosteens as lemons left. The number of peaches left was 18 fewer than the number of mangosteens. How many lemons were given away?
| |
Mangosteens |
Lemons |
Peaches |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 90 |
|
| After |
4 u |
1 u |
4 u - 18 |
198 |
Total number of fruits in the end
= 4 u + 1 u + 4 u - 18
= 9 u - 18
9 u - 18 = 198
9 u = 198 + 18
9 u = 216
1 u = 216 ÷ 9 = 24
Number of peaches at first
= 4 u - 18 + 90
= 4 x 24 - 18 + 90
= 96 - 18 + 90
= 168
The number of lemons and peaches at first was the same.
Number of lemons given away
= 168 - 1 u
= 168 - 24
= 144
Answer(s): 144
