A store owner had the same number of mangoes, dragonfruits and pears at first. After 94 pears, some mangoes and dragonfruits were set aside, there were 109 fruits left. There were five times as many mangoes as dragonfruits left. The number of pears left was 12 less than the number of mangoes. How many dragonfruits were set aside?
| |
Mangoes |
Dragonfruits |
Pears |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 94 |
|
| After |
5 u |
1 u |
5 u - 12 |
109 |
Total number of fruits in the end
= 5 u + 1 u + 5 u - 12
= 11 u - 12
11 u - 12 = 109
11 u = 109 + 12
11 u = 121
1 u = 121 ÷ 11 = 11
Number of pears at first
= 5 u - 12 + 94
= 5 x 11 - 12 + 94
= 55 - 12 + 94
= 137
The number of dragonfruits and pears at first was the same.
Number of dragonfruits set aside
= 137 - 1 u
= 137 - 11
= 126
Answer(s): 126
