PSLEMin had two ribbons of the same length. She cut the first ribbon into equal parts of length 35 cm and to each part she tied 2 silver balls. After that, she cut the second ribbon into equal parts of length 40 cm and to each part she tied 4 green balls. When she finished tying, she counted that there were 48 more green balls than silver balls. How many balls were there altogether?
|
First ribbon |
Second ribbon |
Difference |
Total |
Length of each part |
35 cm |
40 cm |
|
|
Number of balloons tied to each part |
2 silver balloons |
4 green balloons |
|
|
LCM |
280 cm |
280 cm |
|
|
Number of equal parts |
280 ÷ 35 = 8 |
280 ÷ 40 = 7 |
|
|
Number of balloons for each ribbon per set |
8 x 2 = 16 |
4 x 7 = 28 |
28 - 16 = 12 |
16 + 28 = 44 |
LCM of 35 and 40 = 280
Number of sets of 2 silver balls in a length of 280 cm
= 280 ÷ 35
= 8
Number of silver balls in a length of 280 cm
= 8 x 2
= 16
Number of sets of 4 green balls in a length of 280 cm
= 280 ÷ 40
= 7
Number of green balls in a length of 280 cm
= 7 x 4
= 28
Extra number of green balls in a length of 280 cm
= 28 - 16
= 12
Number of sets of balls
= 48 ÷ 12
= 4
Total number of balls in one set of 280 cm of silver balloons and one set of 280 cm of green balloons
= 16 + 28
= 44
Total number of balls of the two ribbons
= 4 x 44
= 176
Answer(s): 176