PSLEHilda had two ribbons of the same length. She cut the first ribbon into equal parts of length 35 cm and to each part she tied 3 grey balls. After that, she cut the second ribbon into equal parts of length 50 cm and to each part she tied 5 pink balls. When she finished tying, she counted that there were 25 more pink balls than grey balls. How many balls were there altogether?
|
First ribbon |
Second ribbon |
Difference |
Total |
Length of each part |
35 cm |
50 cm |
|
|
Number of balloons tied to each part |
3 grey balloons |
5 pink balloons |
|
|
LCM |
350 cm |
350 cm |
|
|
Number of equal parts |
350 ÷ 35 = 10 |
350 ÷ 50 = 7 |
|
|
Number of balloons for each ribbon per set |
10 x 3 = 30 |
5 x 7 = 35 |
35 - 30 = 5 |
30 + 35 = 65 |
LCM of 35 and 50 = 350
Number of sets of 3 grey balls in a length of 350 cm
= 350 ÷ 35
= 10
Number of grey balls in a length of 350 cm
= 10 x 3
= 30
Number of sets of 5 pink balls in a length of 350 cm
= 350 ÷ 50
= 7
Number of pink balls in a length of 350 cm
= 7 x 5
= 35
Extra number of pink balls in a length of 350 cm
= 35 - 30
= 5
Number of sets of balls
= 25 ÷ 5
= 5
Total number of balls in one set of 350 cm of grey balloons and one set of 350 cm of pink balloons
= 30 + 35
= 65
Total number of balls of the two ribbons
= 5 x 65
= 325
Answer(s): 325