13 of the number of ducks that Farmer Simon had was equal to
67 of the number of ducks that Farmer Will had. When Farmer Simon sold 300 of his ducks and Farmer Will bought another 40, the ratio of the number of ducks that Farmer Simon had to the number of ducks Farmer Will had become 3 : 2. What was the total number of ducks that the 2 farmers had at first?
|
Make p the same (1) x 2 = (3) |
Farmer Simon (1) |
Farmer Will (2) |
Make p the same (2) x 3 = (4) |
Before |
36 u |
18 u |
7 u |
21 u |
Change |
- 600 |
- 300 |
+ 40 |
+ 120 |
After |
6 p |
3 p |
2 p |
6 p |
Make the numerators the same.
1x63x6 Farmer Simon's ducks =
6x17x1 Farmer Will's ducks
618 Farmer Simon's ducks =
67 Farmer Will's ducks
36 u - 600 = 21 u + 120
36 u - 21 u = 120 + 600
15 u = 720
1 u = 720 ÷ 15 = 48
Total number of ducks that the 2 farmers had
= 18 u + 7 u
= 25 u
= 25 x 48
= 1200
Answer(s): 1200