14 of the number of cows that Farmer Ethan had was equal to
35 of the number of cows that Farmer Neave had. When Farmer Ethan sold 300 of his cows and Farmer Neave bought another 40, the ratio of the number of cows that Farmer Ethan had to the number of cows Farmer Neave had become 3 : 2. What was the total number of cows that the 2 farmers had at first?
|
Make p the same (1) x 2 = (3) |
Farmer Ethan (1) |
Farmer Neave (2) |
Make p the same (2) x 3 = (4) |
Before |
24 u |
12 u |
5 u |
15 u |
Change |
- 600 |
- 300 |
+ 40 |
+ 120 |
After |
6 p |
3 p |
2 p |
6 p |
Make the numerators the same.
1x34x3 Farmer Ethan's cows =
3x15x1 Farmer Neave's cows
312 Farmer Ethan's cows =
35 Farmer Neave's cows
24 u - 600 = 15 u + 120
24 u - 15 u = 120 + 600
9 u = 720
1 u = 720 ÷ 9 = 80
Total number of cows that the 2 farmers had
= 12 u + 5 u
= 17 u
= 17 x 80
= 1360
Answer(s): 1360