12 of the number of cows that Farmer Luke had was equal to
67 of the number of cows that Farmer Ryan had. When Farmer Luke sold 300 of his cows and Farmer Ryan bought another 40, the ratio of the number of cows that Farmer Luke had to the number of cows Farmer Ryan had become 3 : 2. What was the total number of cows that the 2 farmers had at first?
|
Make p the same (1) x 2 = (3) |
Farmer Luke (1) |
Farmer Ryan (2) |
Make p the same (2) x 3 = (4) |
Before |
24 u |
12 u |
7 u |
21 u |
Change |
- 600 |
- 300 |
+ 40 |
+ 120 |
After |
6 p |
3 p |
2 p |
6 p |
Make the numerators the same.
1x62x6 Farmer Luke's cows =
6x17x1 Farmer Ryan's cows
612 Farmer Luke's cows =
67 Farmer Ryan's cows
24 u - 600 = 21 u + 120
24 u - 21 u = 120 + 600
3 u = 720
1 u = 720 ÷ 3 = 240
Total number of cows that the 2 farmers had
= 12 u + 7 u
= 19 u
= 19 x 240
= 4560
Answer(s): 4560