14 of the number of goats that Farmer Warren had was equal to
25 of the number of goats that Farmer Lee had. When Farmer Warren sold 300 of his goats and Farmer Lee bought another 40, the ratio of the number of goats that Farmer Warren had to the number of goats Farmer Lee had become 7 : 6. What was the total number of goats that the 2 farmers had at first?
|
Make p the same (1) x 6 = (3) |
Farmer Warren (1) |
Farmer Lee (2) |
Make p the same (2) x 7 = (4) |
Before |
48 u |
8 u |
5 u |
35 u |
Change |
- 1800 |
- 300 |
+ 40 |
+ 280 |
After |
42 p |
7 p |
6 p |
42 p |
Make the numerators the same.
1x24x2 Farmer Warren's goats =
2x15x1 Farmer Lee's goats
28 Farmer Warren's goats =
25 Farmer Lee's goats
48 u - 1800 = 35 u + 280
48 u - 35 u = 280 + 1800
13 u = 2080
1 u = 2080 ÷ 13 = 160
Total number of goats that the 2 farmers had
= 8 u + 5 u
= 13 u
= 13 x 160
= 2080
Answer(s): 2080