13 of the number of pigs that Farmer Jenson had was equal to
35 of the number of pigs that Farmer Bobby had. When Farmer Jenson sold 300 of his pigs and Farmer Bobby bought another 40, the ratio of the number of pigs that Farmer Jenson had to the number of pigs Farmer Bobby had become 3 : 5. What was the total number of pigs that the 2 farmers had at first?
|
Make p the same (1) x 5 = (3) |
Farmer Jenson (1) |
Farmer Bobby (2) |
Make p the same (2) x 3 = (4) |
Before |
45 u |
9 u |
5 u |
15 u |
Change |
- 1500 |
- 300 |
+ 40 |
+ 120 |
After |
15 p |
3 p |
5 p |
15 p |
Make the numerators the same.
1x33x3 Farmer Jenson's pigs =
3x15x1 Farmer Bobby's pigs
39 Farmer Jenson's pigs =
35 Farmer Bobby's pigs
45 u - 1500 = 15 u + 120
45 u - 15 u = 120 + 1500
30 u = 1620
1 u = 1620 ÷ 30 = 54
Total number of pigs that the 2 farmers had
= 9 u + 5 u
= 14 u
= 14 x 54
= 756
Answer(s): 756