13 of the number of cows that Farmer Rael had was equal to
34 of the number of cows that Farmer Asher had. When Farmer Rael sold 300 of his cows and Farmer Asher bought another 40, the ratio of the number of cows that Farmer Rael had to the number of cows Farmer Asher had become 7 : 6. What was the total number of cows that the 2 farmers had at first?
|
Make p the same (1) x 6 = (3) |
Farmer Rael (1) |
Farmer Asher (2) |
Make p the same (2) x 7 = (4) |
Before |
54 u |
9 u |
4 u |
28 u |
Change |
- 1800 |
- 300 |
+ 40 |
+ 280 |
After |
42 p |
7 p |
6 p |
42 p |
Make the numerators the same.
1x33x3 Farmer Rael's cows =
3x14x1 Farmer Asher's cows
39 Farmer Rael's cows =
34 Farmer Asher's cows
54 u - 1800 = 28 u + 280
54 u - 28 u = 280 + 1800
26 u = 2080
1 u = 2080 ÷ 26 = 80
Total number of cows that the 2 farmers had
= 9 u + 4 u
= 13 u
= 13 x 80
= 1040
Answer(s): 1040