12 of the number of pigs that Farmer Billy had was equal to
34 of the number of pigs that Farmer Tom had. When Farmer Billy sold 300 of his pigs and Farmer Tom bought another 40, the ratio of the number of pigs that Farmer Billy had to the number of pigs Farmer Tom had become 7 : 6. What was the total number of pigs that the 2 farmers had at first?
|
Make p the same (1) x 6 = (3) |
Farmer Billy (1) |
Farmer Tom (2) |
Make p the same (2) x 7 = (4) |
Before |
36 u |
6 u |
4 u |
28 u |
Change |
- 1800 |
- 300 |
+ 40 |
+ 280 |
After |
42 p |
7 p |
6 p |
42 p |
Make the numerators the same.
1x32x3 Farmer Billy's pigs =
3x14x1 Farmer Tom's pigs
36 Farmer Billy's pigs =
34 Farmer Tom's pigs
36 u - 1800 = 28 u + 280
36 u - 28 u = 280 + 1800
8 u = 2080
1 u = 2080 ÷ 8 = 260
Total number of pigs that the 2 farmers had
= 6 u + 4 u
= 10 u
= 10 x 260
= 2600
Answer(s): 2600