14 of the number of sheep that Farmer Will had was equal to
57 of the number of sheep that Farmer Mark had. When Farmer Will sold 300 of his sheep and Farmer Mark bought another 40, the ratio of the number of sheep that Farmer Will had to the number of sheep Farmer Mark had become 8 : 3. What was the total number of sheep that the 2 farmers had at first?
|
Make p the same (1) x 3 = (3) |
Farmer Will (1) |
Farmer Mark (2) |
Make p the same (2) x 8 = (4) |
Before |
60 u |
20 u |
7 u |
56 u |
Change |
- 900 |
- 300 |
+ 40 |
+ 320 |
After |
24 p |
8 p |
3 p |
24 p |
Make the numerators the same.
1x54x5 Farmer Will's sheep =
5x17x1 Farmer Mark's sheep
520 Farmer Will's sheep =
57 Farmer Mark's sheep
60 u - 900 = 56 u + 320
60 u - 56 u = 320 + 900
4 u = 1220
1 u = 1220 ÷ 4 = 305
Total number of sheep that the 2 farmers had
= 20 u + 7 u
= 27 u
= 27 x 305
= 8235
Answer(s): 8235