14 of the number of sheep that Farmer Neave had was equal to
35 of the number of sheep that Farmer Dylan had. When Farmer Neave sold 300 of his sheep and Farmer Dylan bought another 40, the ratio of the number of sheep that Farmer Neave had to the number of sheep Farmer Dylan had become 6 : 5. What was the total number of sheep that the 2 farmers had at first?
|
Make p the same (1) x 5 = (3) |
Farmer Neave (1) |
Farmer Dylan (2) |
Make p the same (2) x 6 = (4) |
Before |
60 u |
12 u |
5 u |
30 u |
Change |
- 1500 |
- 300 |
+ 40 |
+ 240 |
After |
30 p |
6 p |
5 p |
30 p |
Make the numerators the same.
1x34x3 Farmer Neave's sheep =
3x15x1 Farmer Dylan's sheep
312 Farmer Neave's sheep =
35 Farmer Dylan's sheep
60 u - 1500 = 30 u + 240
60 u - 30 u = 240 + 1500
30 u = 1740
1 u = 1740 ÷ 30 = 58
Total number of sheep that the 2 farmers had
= 12 u + 5 u
= 17 u
= 17 x 58
= 986
Answer(s): 986