15 of the number of chickens that Farmer Eric had was equal to
25 of the number of chickens that Farmer Sam had. When Farmer Eric sold 300 of his chickens and Farmer Sam bought another 40, the ratio of the number of chickens that Farmer Eric had to the number of chickens Farmer Sam had become 5 : 3. What was the total number of chickens that the 2 farmers had at first?
|
Make p the same (1) x 3 = (3) |
Farmer Eric (1) |
Farmer Sam (2) |
Make p the same (2) x 5 = (4) |
Before |
30 u |
10 u |
5 u |
25 u |
Change |
- 900 |
- 300 |
+ 40 |
+ 200 |
After |
15 p |
5 p |
3 p |
15 p |
Make the numerators the same.
1x25x2 Farmer Eric's chickens =
2x15x1 Farmer Sam's chickens
210 Farmer Eric's chickens =
25 Farmer Sam's chickens
30 u - 900 = 25 u + 200
30 u - 25 u = 200 + 900
5 u = 1100
1 u = 1100 ÷ 5 = 220
Total number of chickens that the 2 farmers had
= 10 u + 5 u
= 15 u
= 15 x 220
= 3300
Answer(s): 3300