14 of the number of pigs that Farmer John had was equal to
25 of the number of pigs that Farmer Jenson had. When Farmer John sold 300 of his pigs and Farmer Jenson bought another 40, the ratio of the number of pigs that Farmer John had to the number of pigs Farmer Jenson had become 5 : 4. What was the total number of pigs that the 2 farmers had at first?
|
Make p the same (1) x 4 = (3) |
Farmer John (1) |
Farmer Jenson (2) |
Make p the same (2) x 5 = (4) |
Before |
32 u |
8 u |
5 u |
25 u |
Change |
- 1200 |
- 300 |
+ 40 |
+ 200 |
After |
20 p |
5 p |
4 p |
20 p |
Make the numerators the same.
1x24x2 Farmer John's pigs =
2x15x1 Farmer Jenson's pigs
28 Farmer John's pigs =
25 Farmer Jenson's pigs
32 u - 1200 = 25 u + 200
32 u - 25 u = 200 + 1200
7 u = 1400
1 u = 1400 ÷ 7 = 200
Total number of pigs that the 2 farmers had
= 8 u + 5 u
= 13 u
= 13 x 200
= 2600
Answer(s): 2600