12 of the number of chickens that Farmer Elijah had was equal to
34 of the number of chickens that Farmer Henry had. When Farmer Elijah sold 300 of his chickens and Farmer Henry bought another 40, the ratio of the number of chickens that Farmer Elijah had to the number of chickens Farmer Henry had become 3 : 7. What was the total number of chickens that the 2 farmers had at first?
|
Make p the same (1) x 7 = (3) |
Farmer Elijah (1) |
Farmer Henry (2) |
Make p the same (2) x 3 = (4) |
Before |
42 u |
6 u |
4 u |
12 u |
Change |
- 2100 |
- 300 |
+ 40 |
+ 120 |
After |
21 p |
3 p |
7 p |
21 p |
Make the numerators the same.
1x32x3 Farmer Elijah's chickens =
3x14x1 Farmer Henry's chickens
36 Farmer Elijah's chickens =
34 Farmer Henry's chickens
42 u - 2100 = 12 u + 120
42 u - 12 u = 120 + 2100
30 u = 2220
1 u = 2220 ÷ 30 = 74
Total number of chickens that the 2 farmers had
= 6 u + 4 u
= 10 u
= 10 x 74
= 740
Answer(s): 740