15 of the number of pigs that Farmer Neave had was equal to
34 of the number of pigs that Farmer John had. When Farmer Neave sold 300 of his pigs and Farmer John bought another 40, the ratio of the number of pigs that Farmer Neave had to the number of pigs Farmer John had become 5 : 2. What was the total number of pigs that the 2 farmers had at first?
|
Make p the same (1) x 2 = (3) |
Farmer Neave (1) |
Farmer John (2) |
Make p the same (2) x 5 = (4) |
Before |
30 u |
15 u |
4 u |
20 u |
Change |
- 600 |
- 300 |
+ 40 |
+ 200 |
After |
10 p |
5 p |
2 p |
10 p |
Make the numerators the same.
1x35x3 Farmer Neave's pigs =
3x14x1 Farmer John's pigs
315 Farmer Neave's pigs =
34 Farmer John's pigs
30 u - 600 = 20 u + 200
30 u - 20 u = 200 + 600
10 u = 800
1 u = 800 ÷ 10 = 80
Total number of pigs that the 2 farmers had
= 15 u + 4 u
= 19 u
= 19 x 80
= 1520
Answer(s): 1520