12 of the number of sheep that Farmer George had was equal to
34 of the number of sheep that Farmer Glen had. When Farmer George sold 300 of his sheep and Farmer Glen bought another 40, the ratio of the number of sheep that Farmer George had to the number of sheep Farmer Glen had become 2 : 3. What was the total number of sheep that the 2 farmers had at first?
|
Make p the same (1) x 3 = (3) |
Farmer George (1) |
Farmer Glen (2) |
Make p the same (2) x 2 = (4) |
Before |
18 u |
6 u |
4 u |
8 u |
Change |
- 900 |
- 300 |
+ 40 |
+ 80 |
After |
6 p |
2 p |
3 p |
6 p |
Make the numerators the same.
1x32x3 Farmer George's sheep =
3x14x1 Farmer Glen's sheep
36 Farmer George's sheep =
34 Farmer Glen's sheep
18 u - 900 = 8 u + 80
18 u - 8 u = 80 + 900
10 u = 980
1 u = 980 ÷ 10 = 98
Total number of sheep that the 2 farmers had
= 6 u + 4 u
= 10 u
= 10 x 98
= 980
Answer(s): 980