12 of the number of pigs that Farmer Luis had was equal to
67 of the number of pigs that Farmer Elijah had. When Farmer Luis sold 300 of his pigs and Farmer Elijah bought another 40, the ratio of the number of pigs that Farmer Luis had to the number of pigs Farmer Elijah had become 8 : 5. What was the total number of pigs that the 2 farmers had at first?
|
Make p the same (1) x 5 = (3) |
Farmer Luis (1) |
Farmer Elijah (2) |
Make p the same (2) x 8 = (4) |
Before |
60 u |
12 u |
7 u |
56 u |
Change |
- 1500 |
- 300 |
+ 40 |
+ 320 |
After |
40 p |
8 p |
5 p |
40 p |
Make the numerators the same.
1x62x6 Farmer Luis's pigs =
6x17x1 Farmer Elijah's pigs
612 Farmer Luis's pigs =
67 Farmer Elijah's pigs
60 u - 1500 = 56 u + 320
60 u - 56 u = 320 + 1500
4 u = 1820
1 u = 1820 ÷ 4 = 455
Total number of pigs that the 2 farmers had
= 12 u + 7 u
= 19 u
= 19 x 455
= 8645
Answer(s): 8645