14 of the number of sheep that Farmer Harry had was equal to
34 of the number of sheep that Farmer Riordan had. When Farmer Harry sold 300 of his sheep and Farmer Riordan bought another 40, the ratio of the number of sheep that Farmer Harry had to the number of sheep Farmer Riordan had become 1 : 2. What was the total number of sheep that the 2 farmers had at first?
|
Make p the same (1) x 2 = (3) |
Farmer Harry (1) |
Farmer Riordan (2) |
Make p the same (2) x 1 = (4) |
Before |
24 u |
12 u |
4 u |
4 u |
Change |
- 600 |
- 300 |
+ 40 |
+ 40 |
After |
2 p |
1 p |
2 p |
2 p |
Make the numerators the same.
1x34x3 Farmer Harry's sheep =
3x14x1 Farmer Riordan's sheep
312 Farmer Harry's sheep =
34 Farmer Riordan's sheep
24 u - 600 = 4 u + 40
24 u - 4 u = 40 + 600
20 u = 640
1 u = 640 ÷ 20 = 32
Total number of sheep that the 2 farmers had
= 12 u + 4 u
= 16 u
= 16 x 32
= 512
Answer(s): 512