12 of the number of cows that Farmer Caden had was equal to
57 of the number of cows that Farmer Henry had. When Farmer Caden sold 300 of his cows and Farmer Henry bought another 40, the ratio of the number of cows that Farmer Caden had to the number of cows Farmer Henry had become 4 : 3. What was the total number of cows that the 2 farmers had at first?
|
Make p the same (1) x 3 = (3) |
Farmer Caden (1) |
Farmer Henry (2) |
Make p the same (2) x 4 = (4) |
Before |
30 u |
10 u |
7 u |
28 u |
Change |
- 900 |
- 300 |
+ 40 |
+ 160 |
After |
12 p |
4 p |
3 p |
12 p |
Make the numerators the same.
1x52x5 Farmer Caden's cows =
5x17x1 Farmer Henry's cows
510 Farmer Caden's cows =
57 Farmer Henry's cows
30 u - 900 = 28 u + 160
30 u - 28 u = 160 + 900
2 u = 1060
1 u = 1060 ÷ 2 = 530
Total number of cows that the 2 farmers had
= 10 u + 7 u
= 17 u
= 17 x 530
= 9010
Answer(s): 9010