14 of the number of cows that Farmer Liam had was equal to
25 of the number of cows that Farmer Carl had. When Farmer Liam sold 300 of his cows and Farmer Carl bought another 40, the ratio of the number of cows that Farmer Liam had to the number of cows Farmer Carl had become 4 : 3. What was the total number of cows that the 2 farmers had at first?
|
Make p the same (1) x 3 = (3) |
Farmer Liam (1) |
Farmer Carl (2) |
Make p the same (2) x 4 = (4) |
Before |
24 u |
8 u |
5 u |
20 u |
Change |
- 900 |
- 300 |
+ 40 |
+ 160 |
After |
12 p |
4 p |
3 p |
12 p |
Make the numerators the same.
1x24x2 Farmer Liam's cows =
2x15x1 Farmer Carl's cows
28 Farmer Liam's cows =
25 Farmer Carl's cows
24 u - 900 = 20 u + 160
24 u - 20 u = 160 + 900
4 u = 1060
1 u = 1060 ÷ 4 = 265
Total number of cows that the 2 farmers had
= 8 u + 5 u
= 13 u
= 13 x 265
= 3445
Answer(s): 3445