14 of the number of pigs that Farmer Dylan had was equal to
57 of the number of pigs that Farmer Harry had. When Farmer Dylan sold 300 of his pigs and Farmer Harry bought another 40, the ratio of the number of pigs that Farmer Dylan had to the number of pigs Farmer Harry had become 5 : 2. What was the total number of pigs that the 2 farmers had at first?
|
Make p the same (1) x 2 = (3) |
Farmer Dylan (1) |
Farmer Harry (2) |
Make p the same (2) x 5 = (4) |
Before |
40 u |
20 u |
7 u |
35 u |
Change |
- 600 |
- 300 |
+ 40 |
+ 200 |
After |
10 p |
5 p |
2 p |
10 p |
Make the numerators the same.
1x54x5 Farmer Dylan's pigs =
5x17x1 Farmer Harry's pigs
520 Farmer Dylan's pigs =
57 Farmer Harry's pigs
40 u - 600 = 35 u + 200
40 u - 35 u = 200 + 600
5 u = 800
1 u = 800 ÷ 5 = 160
Total number of pigs that the 2 farmers had
= 20 u + 7 u
= 27 u
= 27 x 160
= 4320
Answer(s): 4320