14 of the number of cows that Farmer Ahmad had was equal to
34 of the number of cows that Farmer Elijah had. When Farmer Ahmad sold 300 of his cows and Farmer Elijah bought another 40, the ratio of the number of cows that Farmer Ahmad had to the number of cows Farmer Elijah had become 5 : 4. What was the total number of cows that the 2 farmers had at first?
|
Make p the same (1) x 4 = (3) |
Farmer Ahmad (1) |
Farmer Elijah (2) |
Make p the same (2) x 5 = (4) |
Before |
48 u |
12 u |
4 u |
20 u |
Change |
- 1200 |
- 300 |
+ 40 |
+ 200 |
After |
20 p |
5 p |
4 p |
20 p |
Make the numerators the same.
1x34x3 Farmer Ahmad's cows =
3x14x1 Farmer Elijah's cows
312 Farmer Ahmad's cows =
34 Farmer Elijah's cows
48 u - 1200 = 20 u + 200
48 u - 20 u = 200 + 1200
28 u = 1400
1 u = 1400 ÷ 28 = 50
Total number of cows that the 2 farmers had
= 12 u + 4 u
= 16 u
= 16 x 50
= 800
Answer(s): 800