15 of the number of sheep that Farmer Will had was equal to
25 of the number of sheep that Farmer Billy had. When Farmer Will sold 300 of his sheep and Farmer Billy bought another 40, the ratio of the number of sheep that Farmer Will had to the number of sheep Farmer Billy had become 5 : 3. What was the total number of sheep that the 2 farmers had at first?
|
Make p the same (1) x 3 = (3) |
Farmer Will (1) |
Farmer Billy (2) |
Make p the same (2) x 5 = (4) |
Before |
30 u |
10 u |
5 u |
25 u |
Change |
- 900 |
- 300 |
+ 40 |
+ 200 |
After |
15 p |
5 p |
3 p |
15 p |
Make the numerators the same.
1x25x2 Farmer Will's sheep =
2x15x1 Farmer Billy's sheep
210 Farmer Will's sheep =
25 Farmer Billy's sheep
30 u - 900 = 25 u + 200
30 u - 25 u = 200 + 900
5 u = 1100
1 u = 1100 ÷ 5 = 220
Total number of sheep that the 2 farmers had
= 10 u + 5 u
= 15 u
= 15 x 220
= 3300
Answer(s): 3300