12 of the number of pigs that Farmer Simon had was equal to
34 of the number of pigs that Farmer Cole had. When Farmer Simon sold 300 of his pigs and Farmer Cole bought another 40, the ratio of the number of pigs that Farmer Simon had to the number of pigs Farmer Cole had become 4 : 3. What was the total number of pigs that the 2 farmers had at first?
|
Make p the same (1) x 3 = (3) |
Farmer Simon (1) |
Farmer Cole (2) |
Make p the same (2) x 4 = (4) |
Before |
18 u |
6 u |
4 u |
16 u |
Change |
- 900 |
- 300 |
+ 40 |
+ 160 |
After |
12 p |
4 p |
3 p |
12 p |
Make the numerators the same.
1x32x3 Farmer Simon's pigs =
3x14x1 Farmer Cole's pigs
36 Farmer Simon's pigs =
34 Farmer Cole's pigs
18 u - 900 = 16 u + 160
18 u - 16 u = 160 + 900
2 u = 1060
1 u = 1060 ÷ 2 = 530
Total number of pigs that the 2 farmers had
= 6 u + 4 u
= 10 u
= 10 x 530
= 5300
Answer(s): 5300