¹₃ of the number of sheep that Farmer Charlie had was equal to ⁵₇ of the number of sheep that Farmer Elijah had. When Farmer Charlie sold 300 of his sheep and Farmer Elijah bought another 40, the ratio of the number of sheep that Farmer Charlie had to the number of sheep Farmer Elijah had become 3 : 2. What was the total number of sheep that the 2 farmers had at first?

	Make p the same (1) x 2 = (3)	Farmer Charlie (1)	Farmer Elijah (2)	Make p the same (2) x 3 = (4)
Before	30 u	15 u	7 u	21 u
Change	- 600	- 300	+ 40	+ 120
After	6 p	3 p	2 p	6 p

Make the numerators the same.
1x53x5 Farmer Charlie's sheep = 5x17x1 Farmer Elijah's sheep
515 Farmer Charlie's sheep = 57 Farmer Elijah's sheep

30 u - 600 = 21 u + 120
30 u - 21 u = 120 + 600
9 u = 720

1 u = 720 ÷ 9 = 80

Total number of sheep that the 2 farmers had
= 15 u + 7 u
= 22 u
= 22 x 80
= 1760

Answer(s): 1760