14 of the number of sheep that Farmer Mark had was equal to
35 of the number of sheep that Farmer Justin had. When Farmer Mark sold 300 of his sheep and Farmer Justin bought another 40, the ratio of the number of sheep that Farmer Mark had to the number of sheep Farmer Justin had become 8 : 5. What was the total number of sheep that the 2 farmers had at first?
|
Make p the same (1) x 5 = (3) |
Farmer Mark (1) |
Farmer Justin (2) |
Make p the same (2) x 8 = (4) |
Before |
60 u |
12 u |
5 u |
40 u |
Change |
- 1500 |
- 300 |
+ 40 |
+ 320 |
After |
40 p |
8 p |
5 p |
40 p |
Make the numerators the same.
1x34x3 Farmer Mark's sheep =
3x15x1 Farmer Justin's sheep
312 Farmer Mark's sheep =
35 Farmer Justin's sheep
60 u - 1500 = 40 u + 320
60 u - 40 u = 320 + 1500
20 u = 1820
1 u = 1820 ÷ 20 = 91
Total number of sheep that the 2 farmers had
= 12 u + 5 u
= 17 u
= 17 x 91
= 1547
Answer(s): 1547