13 of the number of turkeys that Farmer Ethan had was equal to
57 of the number of turkeys that Farmer Luis had. When Farmer Ethan sold 300 of his turkeys and Farmer Luis bought another 40, the ratio of the number of turkeys that Farmer Ethan had to the number of turkeys Farmer Luis had become 5 : 4. What was the total number of turkeys that the 2 farmers had at first?
|
Make p the same (1) x 4 = (3) |
Farmer Ethan (1) |
Farmer Luis (2) |
Make p the same (2) x 5 = (4) |
Before |
60 u |
15 u |
7 u |
35 u |
Change |
- 1200 |
- 300 |
+ 40 |
+ 200 |
After |
20 p |
5 p |
4 p |
20 p |
Make the numerators the same.
1x53x5 Farmer Ethan's turkeys =
5x17x1 Farmer Luis's turkeys
515 Farmer Ethan's turkeys =
57 Farmer Luis's turkeys
60 u - 1200 = 35 u + 200
60 u - 35 u = 200 + 1200
25 u = 1400
1 u = 1400 ÷ 25 = 56
Total number of turkeys that the 2 farmers had
= 15 u + 7 u
= 22 u
= 22 x 56
= 1232
Answer(s): 1232