At first, Christopher had
23 as many erasers as Nora. After Christopher bought another 16 erasers and Nora lost 7 erasers, Christopher had
45 as many erasers as Nora. Find the number of erasers Nora had at first.
Make p the same.
(1) x 5 = (3) |
Christopher
(1) |
Nora
(2) |
Make p the same
(2) x 4 = (4) |
| 10 u |
2 u |
3 u |
12 u |
| + 80 |
+ 16 |
- 7 |
- 28 |
| 20 p |
4 p |
5 p |
20 p |
Make p the same.
(4) = (3)
12 u - 28 = 10 u + 80
12 u - 10 u = 80 + 28
2 u = 108
1 u = 108 ÷ 2 = 54
Number of erasers that Nora had at first
= 3 u
= 3 x 54
= 162
Answer(s): 162
