Three girls used the same number of beads to make bracelets. Jade used
35 of her beads, Xylia used
45 of hers and Abi used
23 of hers. They had a total of 424 beads at first. How many beads did each girl use?
Make the numerators the same.
LCM of 3, 4 and 2 = 12
35 Jade's beads =
45 Xylia's beads =
23 Abi's beads
3x45x4 Jade's beads =
4x35x3 Xylia's beads =
2x63x6 Abi's beads
1220 Jade's beads =
1215 Xylia's beads =
1218 Abi's beads
| |
Jade |
Xylia |
Abi |
| Before |
20 u |
15 u |
18 u |
| Change |
- 12 u |
- 12 u |
- 12 u |
| After |
8 u |
3 u |
6 u |
Total number of beads at first
= 20 u + 15 u + 18 u
= 53 u
53 u = 424
1 u = 424 ÷ 53 = 8
Number of beads that each girl used
= 12 u
= 12 x 8
= 96
Answer(s): 96
