Three girls used the same number of beads to make necklaces. Elyse used
25 of her beads, Victoria used
34 of hers and Kathy used
23 of hers. They had a total of 384 beads at first. How many beads did each girl use?
Make the numerators the same.
LCM of 2, 3 and 2 = 6
25 Elyse's beads =
34 Victoria's beads =
23 Kathy's beads
2x35x3 Elyse's beads =
3x24x2 Victoria's beads =
2x33x3 Kathy's beads
615 Elyse's beads =
68 Victoria's beads =
69 Kathy's beads
| |
Elyse |
Victoria |
Kathy |
| Before |
15 u |
8 u |
9 u |
| Change |
- 6 u |
- 6 u |
- 6 u |
| After |
9 u |
2 u |
3 u |
Total number of beads at first
= 15 u + 8 u + 9 u
= 32 u
32 u = 384
1 u = 384 ÷ 32 = 12
Number of beads that each girl used
= 6 u
= 6 x 12
= 72
Answer(s): 72
